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9p^2+7p-11=0
a = 9; b = 7; c = -11;
Δ = b2-4ac
Δ = 72-4·9·(-11)
Δ = 445
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{445}}{2*9}=\frac{-7-\sqrt{445}}{18} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{445}}{2*9}=\frac{-7+\sqrt{445}}{18} $
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